document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=10326>Question 10326</A>: <I><SPAN STYLE=\"word-break: break-all;\"> -9<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #5538 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=5538\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Please note:  The previously posted solution to this problem is WRONG!\r<BR>\n" );
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document.write( "3x + 3 = 6(x+5)<BR>\n" );
document.write( "3x + 3 = 6x + 30\r<BR>\n" );
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document.write( "Subtract 3x from each side to get the variables on the right side:<BR>\n" );
document.write( "3x - 3x + 3 = 6x - 3x + 30<BR>\n" );
document.write( "3=3x + 30\r<BR>\n" );
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document.write( "Subtract 30 from each side to get the number terms on the left side:<BR>\n" );
document.write( "3 - 30 = 3x + 30 - 30<BR>\n" );
document.write( "-27 = 3x\r<BR>\n" );
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document.write( "Divide both sides by 3:<BR>\n" );
document.write( "x= -9\r<BR>\n" );
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document.write( "R^2 at SCC<BR>\n" );
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