document.write( "Question 77286: If the sides of a sqare are decreased by 2 cm, the area is decreased by 36cm^2. What were teh dimensions of the original Square? This comes from a chapter on factoring and I for the life of me can't see the formula correctly. I have been working out the problem as
\n" ); document.write( "36^2=x^2+x^2-2 but I know this is wrong?? Please HELP\r
\n" ); document.write( "\n" ); document.write( "Debbie
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Algebra.Com's Answer #55375 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
If we have an original square of side x we have the area as:\r
\n" ); document.write( "\n" ); document.write( "\"x%2Ax=x%5E2\"\r
\n" ); document.write( "\n" ); document.write( "So if we decrease the sides by 2 and it results in a decrease of 36 \"cm%5E2\" we get\r
\n" ); document.write( "\n" ); document.write( "\"%28x-2%29%28x-2%29=x%5E2-36\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-4x%2B4=x%5E2-36\" foil the left side\r
\n" ); document.write( "\n" ); document.write( "\"-4x%2B2=-36\" Subtract \"x%5E2\" from both sides\r
\n" ); document.write( "\n" ); document.write( "\"-4x=-40\" Subtract 2 from both sides\r
\n" ); document.write( "\n" ); document.write( "\"x=-40%2F%28-4%29\" Divide both sides by -4\r
\n" ); document.write( "\n" ); document.write( "So the original side is
\n" ); document.write( "\"x=10\"\r
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\n" ); document.write( "Check:
\n" ); document.write( "\"%2810-2%29%2810-2%29=%2810%29%5E2-36\" Plug in x=10
\n" ); document.write( "\"%288%29%288%29=100-36\"
\n" ); document.write( "\"64=64\" works \n" ); document.write( "

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