document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=912354>Question 912354</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the dimensions of the rectangle that has a length of 3 meters more than its width and a perimeter equal in value to its area? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #553744 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=553744\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the dimensions of the rectangle that has a length of 3 meters more than its width and a perimeter equal in value to its area?<BR>\n" );
document.write( "***<BR>\n" );
document.write( "let x=width<BR>\n" );
document.write( "x+3=length<BR>\n" );
document.write( "..<BR>\n" );
document.write( "2(width+length)=2(x+x+3=4x+6=perimeter<BR>\n" );
document.write( "width*length=x(x+3)=x^2+3x=area<BR>\n" );
document.write( "4x+6=x^2+3x<BR>\n" );
document.write( "x^2-x-6=0<BR>\n" );
document.write( "(x-3)(x+2)=0<BR>\n" );
document.write( "x=3<BR>\n" );
document.write( "x+3=6<BR>\n" );
document.write( "dimensions of the rectangle: <BR>\n" );
document.write( "width=3<BR>\n" );
document.write( "length=6 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );