document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=912354>Question 912354</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the dimensions of the rectangle that has a length of 3 meters more than its width and a perimeter equal in value to its area? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #553743 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=553743\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=3+w and 2w+2L=wL.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Substitute for L in the perimeter&area equation.<BR>\n" );
document.write( "2w+2(w+3)=w(w+3)<BR>\n" );
document.write( "Go from that. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );