document.write( "Question 77286: If the sides of a sqare are decreased by 2 cm, the area is decreased by 36cm^2. What were teh dimensions of the original Square? This comes from a chapter on factoring and I for the life of me can't see the formula correctly. I have been working out the problem as
\n" ); document.write( "36^2=x^2+x^2-2 but I know this is wrong?? Please HELP\r
\n" ); document.write( "\n" ); document.write( "Debbie
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Algebra.Com's Answer #55372 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Let the side of the origimal square be of length x.
\n" ); document.write( "The original area is then \"x%5E2\" After decreasing the original side length by 2 (x-2), the new area is decreased by 36 sq.cm.(\"x%5E2-36\").
\n" ); document.write( "So, you can write:
\n" ); document.write( "\"%28x-2%29%5E2+=+x%5E2-36\" Simplify and solve for x.
\n" ); document.write( "\"x%5E2-4x%2B4+=+x%5E2-36\" Subtract \"x%5E2\" from both sides.
\n" ); document.write( "\"-4x%2B4+=+-36\" Subtract 4 from both sides.
\n" ); document.write( "\"-4x+=+-40\" Divide both sides by -4.
\n" ); document.write( "\"x+=+10\"
\n" ); document.write( "The length of the side of the original square is 10 cm.\r
\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "Original area is 10X10 = 100 sq.cm.
\n" ); document.write( "The new area is (10-2)X(10-2) = 8X8 = 64 sq.cm
\n" ); document.write( "The difference: 100-64 = 36 sq.cm.
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