document.write( "Question 77255: If Dr. Suzuki rides his bike to his office, he averages12 miles per hour. If he drives his car, heaverages 36 miles per hour. His time driving is 1/4 hour less than his time bicycling. How far is his office? \n" ); document.write( "
Algebra.Com's Answer #55369 by ankor@dixie-net.com(22740)\"\" \"About 
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If he averages 12 miles per hour on his bike, and he averages 36 miles per hour
\n" ); document.write( "if he drives. His time driving is 1/4 hour less than his time bicycling. How far is his office?
\n" ); document.write( ":
\n" ); document.write( "Let t = time on the bike
\n" ); document.write( "Then (t-.25) = time in the car
\n" ); document.write( ":
\n" ); document.write( "It's easy to find t, then we can find the distance from that:
\n" ); document.write( "Write a distance equation; Distance = Speed * time
\n" ); document.write( ":
\n" ); document.write( "car dist = bike dist
\n" ); document.write( "36(t-.25) = 12t
\n" ); document.write( "36t - 9 = 12t
\n" ); document.write( "36t - 12t = +9
\n" ); document.write( "24t = 9
\n" ); document.write( "t = 9/24
\n" ); document.write( "t = .375 hrs
\n" ); document.write( ":
\n" ); document.write( "Find distance using time on the bike:
\n" ); document.write( ".375 * 12 = 4.5 miles
\n" ); document.write( ":
\n" ); document.write( "Check solution using time in the car:
\n" ); document.write( "(.375 -.25) * 36
\n" ); document.write( ".125 * 36 = 4.5 miles also
\n" ); document.write( ":
\n" ); document.write( "Make sense to you?\r
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