document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=912244>Question 912244</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.what will be the diagonal of a square whose perimeter is 60m?\r<BR>\n" );
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document.write( "2.The sides of a rectangular field of area 726 sq meters are in the ratio 3:2 . find the length of its diagonal correct up to one decimal place ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #553669 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=553669\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I'll do the first one to get you started\r<BR>\n" );
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document.write( "# 1 what will be the diagonal of a square whose perimeter is 60m?\r<BR>\n" );
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document.write( "Side Length = 60/4 = 15\r<BR>\n" );
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document.write( "a^2 + b^2 = c^2\r<BR>\n" );
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document.write( "15^2 + 15^2 = c^2\r<BR>\n" );
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document.write( "225 + 225 = c^2\r<BR>\n" );
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document.write( "c^2 = 2*225\r<BR>\n" );
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document.write( "c = sqrt(2*225)\r<BR>\n" );
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document.write( "c = sqrt(2)*sqrt(225)\r<BR>\n" );
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document.write( "c = sqrt(2)*15\r<BR>\n" );
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document.write( "c = 15*sqrt(2) <---- Exact length\r<BR>\n" );
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document.write( "c = 21.2132 <---- Approximate length\r<BR>\n" );
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document.write( " </SPAN>\n" );
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