document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=912220>Question 912220</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm trying to determine whether or not the diagrams contain enough information to reach the given conclusion. Any help is greatly appreciated! Here's the image: http://i.imgur.com/NC5S6m0.jpg </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #553655 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=553655\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First one: Yes, because you use the LL theorem and then use CPCTC\r<BR>\n" );
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document.write( "Second one: same idea as the first one, but use HL instead of LL\r<BR>\n" );
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document.write( "Third one: use the SSS theorem and then use CPCTC to find that angle APC = BPC. Since they are congruent and a linear pair of angles, this means they are both 90 degrees. So this one is \"yes\" as well\r<BR>\n" );
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document.write( "Fourth one: You could easily move point C around while still maintaining the fact that AP = BP and preserving the right angles. So there isn't enough info to figure out if C is on PQ </SPAN>\n" );
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