document.write( "Question 912144: The smaller of two numbers is 12 less than the larger. Four times the larger exceeds 3 times the smaller by 90. Find the numbers. \n" ); document.write( "
Algebra.Com's Answer #553621 by JulietG(1812)![]() ![]() You can put this solution on YOUR website! B = A - 12 \n" ); document.write( "4A = 3B + 90 \n" ); document.write( "Substitute the value of B from the first equation into the second \n" ); document.write( "4A = 3B = 90 \n" ); document.write( "4A = 3(A-12) +90 \n" ); document.write( "4A = 3A - 36 + 90 \n" ); document.write( "4A = 3A + 54 \n" ); document.write( "A = 54 \n" ); document.write( "If the larger number is 54, then the smaller number is 42. Check: \n" ); document.write( "Four times the larger (4*54=216) exceeds 3 times the smaller (3*42=126) by 90 (126+90=216) \n" ); document.write( " |