document.write( "Question 912133: Hi,\r
\n" ); document.write( "\n" ); document.write( "solve for y\r
\n" ); document.write( "\n" ); document.write( "2y/y-1 = 1 2/3\r
\n" ); document.write( "\n" ); document.write( "a)y = -5
\n" ); document.write( "b)y = -1
\n" ); document.write( "c)y = 1
\n" ); document.write( "d)y = 5
\n" ); document.write( "

Algebra.Com's Answer #553595 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
\"2y%2F%28y-1%29+=+1+%2B2%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "\"2y%2F%28y-1%29+=+5%2F3\" cross multiply\r
\n" ); document.write( "\n" ); document.write( "\"3%2A2y+=+5%28y-1%29\"\r
\n" ); document.write( "\n" ); document.write( "\"6y+=+5y-5\"\r
\n" ); document.write( "\n" ); document.write( "\"6y-5y=-5\"\r
\n" ); document.write( "\n" ); document.write( "\"y=-5\"\r
\n" ); document.write( "\n" ); document.write( "answer: a)\"y+=+-5\"
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