document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=77264>Question 77264</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you find the slope of the line: 15x-3y=-135 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #55358 by </B><A HREF=/tutors/aboutme.mpl?userid=avidreader27><B>avidreader27(9)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=avidreader27><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=55358\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> to find the slope of this equation, you first need to get it in the proper form of an equation of a line, which is:\r<BR>\n" );
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document.write( "y=mx+b   where m is the slope of the line, and b is the y-intercept.\r<BR>\n" );
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document.write( "15x-3y = -135\r<BR>\n" );
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document.write( "solve the equation for y in terms of x>\r<BR>\n" );
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document.write( "-3y = -15x - 135\r<BR>\n" );
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document.write( "divide every term by -3 to get:\r<BR>\n" );
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document.write( "y = 5x+45\r<BR>\n" );
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document.write( "the slope of the line in this case is 5.\r<BR>\n" );
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document.write( "Hope this helps!!! </SPAN>\n" );
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