document.write( "Question 912112: Solve the following word problem.
\n" ); document.write( "Money is invested at two rates of interest. One rate is 5% and the other is 4%. If there is $800 more invested at 5% than at 4%, find the amount invested at each rate if the total annual interest received is $670. Let x = amount invested at 5% and y = amount invested at 4%. Then the system that models the problem is {x = y + 800 and 0.05x + 0.04y = 670}. Solve the system by using the method of addition.
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Algebra.Com's Answer #553578 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
We don't know the total invested.
\n" ); document.write( "We know the difference in the two accounts.
\n" ); document.write( "We know that the interest for the two accounts is $670
\n" ); document.write( "0.05*x+0.04*y=670
\n" ); document.write( "We know that the account at 5% has $800 more.
\n" ); document.write( "x=800+y
\n" ); document.write( "We substitute for x
\n" ); document.write( "0.05*(800+y)+0.04*y=670
\n" ); document.write( "We multiply out
\n" ); document.write( "40+0.05y+0.04*y=670
\n" ); document.write( "We combine like terms.
\n" ); document.write( "0.09*y=630
\n" ); document.write( "Isolate y
\n" ); document.write( "y=$7000 at 4%
\n" ); document.write( "x=800+y
\n" ); document.write( "Calculate x
\n" ); document.write( "x=$7800 at 5%
\n" ); document.write( "Now,we know the total invested is: 14800
\n" ); document.write( "Total invested $7800+$7000=$14800
\n" ); document.write( "We check
\n" ); document.write( "0.05*7800+0.04*7000=670
\n" ); document.write( "390+280=670
\n" ); document.write( "670=670
\n" ); document.write( "Since this statement is TRUE and neither x nor y is negative all is well.
\n" ); document.write( "codeintmt\r
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\n" ); document.write( "\n" ); document.write( "But you want it solved using elimination or addition\r
\n" ); document.write( "\n" ); document.write( "0.05*x+0.04*y=670
\n" ); document.write( "x=800+y
\n" ); document.write( "x-y=800
\n" ); document.write( "0.05*x+0.04*y=670
\n" ); document.write( "multiply by 100
\n" ); document.write( "5*x+4*y=67000
\n" ); document.write( "x-y=800
\n" ); document.write( "multiply by 6
\n" ); document.write( "4x-4y=3200
\n" ); document.write( "5*x+4*y=67000
\n" ); document.write( "add
\n" ); document.write( "9x=70200
\n" ); document.write( "x=7800 at 5%
\n" ); document.write( "y=7000 at 4%
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