document.write( "Question 912107: tom travels 8 mi/hr. louis leaves 10 minute later from the same spot traveling at 18 mi/hr. how long will it take for louise to catch tom? \n" ); document.write( "
Algebra.Com's Answer #553577 by richwmiller(17219) You can put this solution on YOUR website! Gaining speed 18 -8= 10 mph \n" ); document.write( "Headstart 8*0.16666667 =1.33333333 miles \n" ); document.write( "Time to catch up 1.33333333/10=0.13333333 hours \n" ); document.write( "Time to catch up =8 minutes \n" ); document.write( "Algebraic solution \n" ); document.write( "8(t+0.16666667)=18t \n" ); document.write( "8t+1.33333333=18t \n" ); document.write( "1.33333333=18t-8t \n" ); document.write( "1.33333333=10t \n" ); document.write( "t=0.13333333 hours \n" ); document.write( "Distance to meeting 0.13333333*18=2.4 miles \n" ); document.write( "code drtch1\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |