document.write( "Question 912085: The perimeter of a rectangula town is 24m.if the are of the town is 35cm^2,how wide is the town? \n" ); document.write( "
Algebra.Com's Answer #553552 by Alan3354(69443)\"\" \"About 
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The perimeter of a rectangula town is 24m.if the are of the town is 35cm^2,how wide is the town?
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\n" ); document.write( "P = 2W + 2L = 24m = 2400 cm
\n" ); document.write( "W + L = 1200
\n" ); document.write( "W*L = 35
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\n" ); document.write( "W + L = 1200 --> L = 1200 - W
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\n" ); document.write( "W*L = 35
\n" ); document.write( "W*(1200 - W) = 35
\n" ); document.write( "W^2 - 1200W + 35 = 0
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B-1200x%2B35+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-1200%29%5E2-4%2A1%2A35=1439860\".
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\n" ); document.write( " Discriminant d=1439860 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--1200%2B-sqrt%28+1439860+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%28-1200%29%2Bsqrt%28+1439860+%29%29%2F2%5C1+=+1199.97083262439\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-1200%29-sqrt%28+1439860+%29%29%2F2%5C1+=+0.0291673756131559\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B-1200x%2B35\" can be factored:
\n" ); document.write( " \"1x%5E2%2B-1200x%2B35+=+%28x-1199.97083262439%29%2A%28x-0.0291673756131559%29\"
\n" ); document.write( " Again, the answer is: 1199.97083262439, 0.0291673756131559.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-1200%2Ax%2B35+%29\"

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\n" ); document.write( "W = 0.029167 cm
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