document.write( "Question 912018: A curve has an equation of \"y=xe%5Ex\". The curve has a stationary point at P.
\n" ); document.write( "(i)Find,in terms of e, the coordinates of P and determine the nature of this stationary point.
\n" ); document.write( "The normal to the curve at the point Q (1,e) meets the x-axis at R and the y-axis at S.
\n" ); document.write( "(ii)Find in terms of e, the area of the triangle ORS, where O is the origin.
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Algebra.Com's Answer #553544 by Alan3354(69443)\"\" \"About 
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A curve has an equation of \"y=xe%5Ex\". The curve has a stationary point at P.
\n" ); document.write( "(i)Find,in terms of e, the coordinates of P and determine the nature of this stationary point.
\n" ); document.write( "y' = \"e%5Ex+%2B+x%2Ae%5Ex\"
\n" ); document.write( "\"e%5Ex+%2B+x%2Ae%5Ex+=+0\"
\n" ); document.write( "e^x = 0 (Ignore)
\n" ); document.write( "x = -1 is a local minimum
\n" ); document.write( "y = 1/e
\n" ); document.write( "(-1,1/e) is a local minimum
\n" ); document.write( "===============================
\n" ); document.write( "The normal to the curve at the point Q (1,e) meets the x-axis at R and the y-axis at S.
\n" ); document.write( "(ii)Find in terms of e, the area of the triangle ORS, where O is the origin.
\n" ); document.write( "y' = \"e%5Ex+%2B+x%2Ae%5Ex\"
\n" ); document.write( "y'(1) = 2e
\n" ); document.write( "m of the normal = -1/(2e)
\n" ); document.write( "y - e = (-1/2e)*(x - 1) = -x/(2e) + 1/(2e)
\n" ); document.write( "\"y+=+-x%2F%282e%29+%2B+%282e%5E2+%2B+1%29%2F%282e%29\"
\n" ); document.write( "--> S((2e^2 + 1)/(2e),0)
\n" ); document.write( "--------------
\n" ); document.write( "\"y+=+-x%2F%282e%29+%2B+%282e%5E2+%2B+1%29%2F%282e%29+=+0\"
\n" ); document.write( "\"-x+%2B+%282e%5E2+%2B+1%29+=+0\"
\n" ); document.write( "x = 2e^2 + 1 --> R(2e^2 + 1,0)
\n" ); document.write( "--------------
\n" ); document.write( "Area = bh/2
\n" ); document.write( "= \"%28%282e%5E2+%2B+1%29%2F%282e%29%29%2A%282e%5E2+%2B+1%29%2F2\"
\n" ); document.write( "= \"%28%282e%5E2+%2B+1%29%5E2%2F%284e%29%29\"
\n" ); document.write( "
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