document.write( "Question 912018: A curve has an equation of . The curve has a stationary point at P.
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document.write( "(i)Find,in terms of e, the coordinates of P and determine the nature of this stationary point.
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document.write( "The normal to the curve at the point Q (1,e) meets the x-axis at R and the y-axis at S.
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document.write( "(ii)Find in terms of e, the area of the triangle ORS, where O is the origin. \n" );
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Algebra.Com's Answer #553544 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! A curve has an equation of \n" ); document.write( "(i)Find,in terms of e, the coordinates of P and determine the nature of this stationary point. \n" ); document.write( "y' = \n" ); document.write( " \n" ); document.write( "e^x = 0 (Ignore) \n" ); document.write( "x = -1 is a local minimum \n" ); document.write( "y = 1/e \n" ); document.write( "(-1,1/e) is a local minimum \n" ); document.write( "=============================== \n" ); document.write( "The normal to the curve at the point Q (1,e) meets the x-axis at R and the y-axis at S. \n" ); document.write( "(ii)Find in terms of e, the area of the triangle ORS, where O is the origin. \n" ); document.write( "y' = \n" ); document.write( "y'(1) = 2e \n" ); document.write( "m of the normal = -1/(2e) \n" ); document.write( "y - e = (-1/2e)*(x - 1) = -x/(2e) + 1/(2e) \n" ); document.write( " \n" ); document.write( "--> S((2e^2 + 1)/(2e),0) \n" ); document.write( "-------------- \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x = 2e^2 + 1 --> R(2e^2 + 1,0) \n" ); document.write( "-------------- \n" ); document.write( "Area = bh/2 \n" ); document.write( "= \n" ); document.write( "= \n" ); document.write( " \n" ); document.write( " |