document.write( "Question 912055: Find the equation of each of these straight lines in the form of y=mx+c.\r
\n" ); document.write( "\n" ); document.write( "b) perpendicular to the line 3x+4y=5 passing through (3,-2)
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Algebra.Com's Answer #553525 by mananth(16946)\"\" \"About 
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3 x + 4 y = 5
\n" ); document.write( "Find the slope of this line
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\n" ); document.write( "4 y = -3 x + 5
\n" ); document.write( "Divide by 4
\n" ); document.write( " y = - 3/ 4 x + 1 1/4
\n" ); document.write( "Compare this equation with y=mx+b, m= slope & b= y intercept
\n" ); document.write( "slope m = - 3/4
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\n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal 1 1/3
\n" ); document.write( "Because m1*m2 =-1
\n" ); document.write( "The slope of the required line will be 1 1/3
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\n" ); document.write( "m= 1 1/3 ,point ( 3 , -2 )
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "-2 = 4 + b
\n" ); document.write( "b= -6
\n" ); document.write( "m= 1 1/3
\n" ); document.write( "The required equation is y =4/ 3 x -6
\n" ); document.write( "m.ananth@hotmail.ca
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