document.write( "Question 912055: Find the equation of each of these straight lines in the form of y=mx+c.\r
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document.write( "b) perpendicular to the line 3x+4y=5 passing through (3,-2) \n" );
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Algebra.Com's Answer #553525 by mananth(16946)![]() ![]() You can put this solution on YOUR website! 3 x + 4 y = 5 \n" ); document.write( "Find the slope of this line \n" ); document.write( " \n" ); document.write( "4 y = -3 x + 5 \n" ); document.write( "Divide by 4 \n" ); document.write( " y = - 3/ 4 x + 1 1/4 \n" ); document.write( "Compare this equation with y=mx+b, m= slope & b= y intercept \n" ); document.write( "slope m = - 3/4 \n" ); document.write( " \n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal 1 1/3 \n" ); document.write( "Because m1*m2 =-1 \n" ); document.write( "The slope of the required line will be 1 1/3 \n" ); document.write( " \n" ); document.write( "m= 1 1/3 ,point ( 3 , -2 ) \n" ); document.write( "Find b by plugging the values of m & the point in \n" ); document.write( "y=mx+b \n" ); document.write( "-2 = 4 + b \n" ); document.write( "b= -6 \n" ); document.write( "m= 1 1/3 \n" ); document.write( "The required equation is y =4/ 3 x -6 \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |