document.write( "Question 912050: a man has $16000 which he places at interest,part at 3 1/2 percent the rest at 4 percent.his total annual income from this investment is $597.50.how much is invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #553522 by mananth(16946)\"\" \"About 
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Part I 3.50% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 4.00% per annum ------------ Amount invested = y
\n" ); document.write( " 16000
\n" ); document.write( "Interest----- 597.50
\n" ); document.write( "
\n" ); document.write( "Part I 3.50% per annum ---x
\n" ); document.write( "Part II 4.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 16000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "3.50% x + 4.00% y= 597.5
\n" ); document.write( "Multiply by 100
\n" ); document.write( "3.5 x + 4 y= 59750.00 --------2
\n" ); document.write( "Multiply (1) by -3.5
\n" ); document.write( "we get
\n" ); document.write( "-3.5 x -3.5 y= -56000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x 0.5 y= 3750
\n" ); document.write( "divide by 0.5
\n" ); document.write( " y = 7500
\n" ); document.write( "Part I 3.50% $ 8500
\n" ); document.write( "Part II 4.00% $ 7500
\n" ); document.write( "
\n" ); document.write( "CHECK
\n" ); document.write( "8500 --------- 3.50% ------- 297.50
\n" ); document.write( "7500 ------------- 4.00% ------- 300.00
\n" ); document.write( "Total -------------------- 597.50
\n" ); document.write( "
\n" ); document.write( "m.ananth@hotmail.ca
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