document.write( "Question 911970: determine the solution sets of the following systems of linear equation by elimination.\r
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\n" ); document.write( "\n" ); document.write( "6x+2y=-10
\n" ); document.write( "-5x-3y=11
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Algebra.Com's Answer #553470 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition

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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"6%2Ax%2B2%2Ay=-10\"
\n" ); document.write( " \"-5%2Ax-3%2Ay=11\"
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\n" ); document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).
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\n" ); document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.
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\n" ); document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 6 and -5 to some equal number, we could try to get them to the LCM.
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\n" ); document.write( " Since the LCM of 6 and -5 is -30, we need to multiply both sides of the top equation by -5 and multiply both sides of the bottom equation by -6 like this:
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\n" ); document.write( " \"-5%2A%286%2Ax%2B2%2Ay%29=%28-10%29%2A-5\" Multiply the top equation (both sides) by -5
\n" ); document.write( " \"-6%2A%28-5%2Ax-3%2Ay%29=%2811%29%2A-6\" Multiply the bottom equation (both sides) by -6
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\n" ); document.write( " So after multiplying we get this:
\n" ); document.write( " \"-30%2Ax-10%2Ay=50\"
\n" ); document.write( " \"30%2Ax%2B18%2Ay=-66\"
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\n" ); document.write( " Notice how -30 and 30 add to zero (ie \"-30%2B30=0\")
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\n" ); document.write( " Now add the equations together. In order to add 2 equations, group like terms and combine them
\n" ); document.write( " \"%28-30%2Ax%2B30%2Ax%29-10%2Ay%2B18%2Ay%29=50-66\"
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\n" ); document.write( " \"%28-30%2B30%29%2Ax-10%2B18%29y=50-66\"
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\n" ); document.write( " \"cross%28-30%2B30%29%2Ax%2B%28-10%2B18%29%2Ay=50-66\" Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.
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\n" ); document.write( " So after adding and canceling out the x terms we're left with:
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\n" ); document.write( " \"8%2Ay=-16\"
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\n" ); document.write( " \"y=-16%2F8\" Divide both sides by \"8\" to solve for y
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\n" ); document.write( " \"y=-2\" Reduce
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\n" ); document.write( " Now plug this answer into the top equation \"6%2Ax%2B2%2Ay=-10\" to solve for x
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\n" ); document.write( " \"6%2Ax%2B2%28-2%29=-10\" Plug in \"y=-2\"
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\n" ); document.write( " \"6%2Ax-4=-10\" Multiply
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\n" ); document.write( " \"6%2Ax=-10%2B4\" Subtract \"-4\" from both sides
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\n" ); document.write( " \"6%2Ax=-6\" Combine the terms on the right side
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\n" ); document.write( " \"cross%28%281%2F6%29%286%29%29%2Ax=%28-6%29%281%2F6%29\" Multiply both sides by \"1%2F6\". This will cancel out \"6\" on the left side.
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\n" ); document.write( " \"x=-1\" Multiply the terms on the right side
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\n" ); document.write( " So our answer is
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\n" ); document.write( " \"x=-1\", \"y=-2\"
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\n" ); document.write( " which also looks like
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\n" ); document.write( " (\"-1\", \"-2\")
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\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
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\n" ); document.write( " \"6%2Ax%2B2%2Ay=-10\"
\n" ); document.write( " \"-5%2Ax-3%2Ay=11\"
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\n" ); document.write( " we get
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\n" ); document.write( " graph of \"6%2Ax%2B2%2Ay=-10\" (red) \"-5%2Ax-3%2Ay=11\" (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).
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\n" ); document.write( " and we can see that the two equations intersect at (\"-1\",\"-2\"). This verifies our answer.
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