document.write( "Question 911966: Determine the solution sets of the following systems of linear equation by elimination.\r
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\n" ); document.write( "\n" ); document.write( "3x-8y=-18
\n" ); document.write( "x+y=1
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Algebra.Com's Answer #553468 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition

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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"3%2Ax-8%2Ay=-18\"
\n" ); document.write( " \"1%2Ax%2B1%2Ay=1\"
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\n" ); document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).
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\n" ); document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.
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\n" ); document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 3 and 1 to some equal number, we could try to get them to the LCM.
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\n" ); document.write( " Since the LCM of 3 and 1 is 3, we need to multiply both sides of the top equation by 1 and multiply both sides of the bottom equation by -3 like this:
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\n" ); document.write( " \"1%2A%283%2Ax-8%2Ay%29=%28-18%29%2A1\" Multiply the top equation (both sides) by 1
\n" ); document.write( " \"-3%2A%281%2Ax%2B1%2Ay%29=%281%29%2A-3\" Multiply the bottom equation (both sides) by -3
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\n" ); document.write( " So after multiplying we get this:
\n" ); document.write( " \"3%2Ax-8%2Ay=-18\"
\n" ); document.write( " \"-3%2Ax-3%2Ay=-3\"
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\n" ); document.write( " Notice how 3 and -3 add to zero (ie \"3%2B-3=0\")
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\n" ); document.write( " Now add the equations together. In order to add 2 equations, group like terms and combine them
\n" ); document.write( " \"%283%2Ax-3%2Ax%29-8%2Ay-3%2Ay%29=-18-3\"
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\n" ); document.write( " \"%283-3%29%2Ax-8-3%29y=-18-3\"
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\n" ); document.write( " \"cross%283%2B-3%29%2Ax%2B%28-8-3%29%2Ay=-18-3\" Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.
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\n" ); document.write( " So after adding and canceling out the x terms we're left with:
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\n" ); document.write( " \"-11%2Ay=-21\"
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\n" ); document.write( " \"y=-21%2F-11\" Divide both sides by \"-11\" to solve for y
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\n" ); document.write( " \"y=21%2F11\" Reduce
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\n" ); document.write( " Now plug this answer into the top equation \"3%2Ax-8%2Ay=-18\" to solve for x
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\n" ); document.write( " \"3%2Ax-8%2821%2F11%29=-18\" Plug in \"y=21%2F11\"
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\n" ); document.write( " \"3%2Ax-168%2F11=-18\" Multiply
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\n" ); document.write( " \"3%2Ax-168%2F11=-18\" Reduce
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\n" ); document.write( " \"3%2Ax=-18%2B168%2F11\" Subtract \"-168%2F11\" from both sides
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\n" ); document.write( " \"3%2Ax=-198%2F11%2B168%2F11\" Make -18 into a fraction with a denominator of 11
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\n" ); document.write( " \"3%2Ax=-30%2F11\" Combine the terms on the right side
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\n" ); document.write( " \"cross%28%281%2F3%29%283%29%29%2Ax=%28-30%2F11%29%281%2F3%29\" Multiply both sides by \"1%2F3\". This will cancel out \"3\" on the left side.
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\n" ); document.write( " \"x=-10%2F11\" Multiply the terms on the right side
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\n" ); document.write( " So our answer is
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\n" ); document.write( " \"x=-10%2F11\", \"y=21%2F11\"
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\n" ); document.write( " which also looks like
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\n" ); document.write( " (\"-10%2F11\", \"21%2F11\")
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\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
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\n" ); document.write( " \"3%2Ax-8%2Ay=-18\"
\n" ); document.write( " \"1%2Ax%2B1%2Ay=1\"
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\n" ); document.write( " we get
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\n" ); document.write( " graph of \"3%2Ax-8%2Ay=-18\" (red) \"1%2Ax%2B1%2Ay=1\" (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).
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\n" ); document.write( " and we can see that the two equations intersect at (\"-10%2F11\",\"21%2F11\"). This verifies our answer.

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