document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=911963>Question 911963</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For what value of k  are the graphs of 12y=-3x+8 and 6y=kx-5 perpendicular? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #553464 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=553464\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For what value of k  are the graphs of 12y=-3x+8 and 6y=kx-5 perpendicular?<BR>\n" );
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document.write( "Find the slopes::<BR>\n" );
document.write( "y = -3/12 *x + 2/3<BR>\n" );
document.write( "slope = -1/4<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "y = (k/6)x - (5/6)<BR>\n" );
document.write( "slope = k/6<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "To be perpendicular, solve <BR>\n" );
document.write( "(-1/4)(k/6) = -1<BR>\n" );
document.write( "Solve for \"k\"::<BR>\n" );
document.write( "(1/4)(k/6) = 1<BR>\n" );
document.write( "k = 24<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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