document.write( "Question 911762: Marsha and Kan both invested money on March 1, 2007. Marsha invested $9,000 at Bank A where the interest was compounded quarterly. Jan invested $6,000 at Bank B where the interest was compounded continuously. On March 1, 2012, Marsha had a balance of $11,789.68 while Jan had a balance of $7,504.50. What was the interest at each bank? \n" ); document.write( "
Algebra.Com's Answer #553389 by ankor@dixie-net.com(22740)\"\" \"About 
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Marsha and Kan both invested money on March 1, 2007.
\n" ); document.write( " Marsha invested $9,000 at Bank A where the interest was compounded quarterly.
\n" ); document.write( " Jan invested $6,000 at Bank B where the interest was compounded continuously.
\n" ); document.write( " On March 1, 2012, Marsha had a balance of $11,789.68 while Jan had a balance of $7,504.50.
\n" ); document.write( " What was the interest at each bank?
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\n" ); document.write( "From the information given, we know both had money invested for 5 yrs
\n" ); document.write( ":
\n" ); document.write( "M
\n" ); document.write( "\"9000%281%2B%28r%2F4%29%29%5E%285%2A4%29\" = 11789.68
\n" ); document.write( "\"%281%2B%28r%2F4%29%29%5E20\" = \"11789.68%2F9000\"
\n" ); document.write( "use logs here
\n" ); document.write( "\"log%28%281%2B%28r%2F4%29%29%5E20%29\" = \"log%2811789.68%2F9000%29\"
\n" ); document.write( "\"log%28%281%2B%28r%2F4%29%29%5E20%29\" = .1172595
\n" ); document.write( "\"log%28%281%2B%28r%2F4%29%29%29\" = \"1172595%2F20\"
\n" ); document.write( "\"log%281%2B%28r%2F4%29%29\" = .005862975
\n" ); document.write( "find the antilog
\n" ); document.write( "1 + \"r%2F4\" = 1.0136
\n" ); document.write( "\"r%2F4\" = 1.0136 - 1
\n" ); document.write( "\"r%2F4\" = .0136
\n" ); document.write( "mult both sides fy 4
\n" ); document.write( "r = .054366 ~ 5.44% interest
\n" ); document.write( ":
\n" ); document.write( "J
\n" ); document.write( "\"6000%2Ae%5E%285r%29\" = 7504.50
\n" ); document.write( "\"e%5E%285r%29\" = \"7504.50%2F6000\"
\n" ); document.write( "use natural logs here, ln of e = 1, so we have a simple equation
\n" ); document.write( "5r = \"ln%287504.50%2F6000%29\"
\n" ); document.write( "5r = .21046
\n" ); document.write( "r = \".2237%2F5\"
\n" ); document.write( "r = .04475 ~ 4.475% interest
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