document.write( "Question 911762: Marsha and Kan both invested money on March 1, 2007. Marsha invested $9,000 at Bank A where the interest was compounded quarterly. Jan invested $6,000 at Bank B where the interest was compounded continuously. On March 1, 2012, Marsha had a balance of $11,789.68 while Jan had a balance of $7,504.50. What was the interest at each bank? \n" ); document.write( "
Algebra.Com's Answer #553389 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Marsha and Kan both invested money on March 1, 2007. \n" ); document.write( " Marsha invested $9,000 at Bank A where the interest was compounded quarterly. \n" ); document.write( " Jan invested $6,000 at Bank B where the interest was compounded continuously. \n" ); document.write( " On March 1, 2012, Marsha had a balance of $11,789.68 while Jan had a balance of $7,504.50. \n" ); document.write( " What was the interest at each bank? \n" ); document.write( ": \n" ); document.write( "From the information given, we know both had money invested for 5 yrs \n" ); document.write( ": \n" ); document.write( "M \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "use logs here \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "find the antilog \n" ); document.write( "1 + \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "mult both sides fy 4 \n" ); document.write( "r = .054366 ~ 5.44% interest \n" ); document.write( ": \n" ); document.write( "J \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "use natural logs here, ln of e = 1, so we have a simple equation \n" ); document.write( "5r = \n" ); document.write( "5r = .21046 \n" ); document.write( "r = \n" ); document.write( "r = .04475 ~ 4.475% interest \n" ); document.write( ":\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |