document.write( "Question 911773: The function f is a fifth-degree polynomial help?
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document.write( "The function f is a fifth-degree polynomial with
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document.write( "the x-intercepts -1, 4, and 9,
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document.write( "y-intercept 36 and
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document.write( "f (x) ≥ 0 for x ≤ 9. \r
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document.write( "Find f (x). \r
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document.write( "f (x) = \r
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document.write( "Please explain,
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document.write( "Thanks \n" );
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Algebra.Com's Answer #553378 by rothauserc(4718) You can put this solution on YOUR website! We are given; the x-intercepts -1, 4, and 9, \n" ); document.write( "y-intercept 36 and \n" ); document.write( "f(x) ≥ 0 for x ≤ 9, therefore \n" ); document.write( "f(x) = (x+1)*(x-4)*(x-9)*g(x) where \n" ); document.write( "g(x) is a quadratic equation of the form \n" ); document.write( "Ax^2 + Bx +C \n" ); document.write( "To determine g(x): \n" ); document.write( "We need f(x) ≥ 0 for x ≤ 9. \n" ); document.write( "==> (x + 1)(x - 4)(x - 9)g(x) ≥ 0 for x ≤ 9. \n" ); document.write( "Since we need g(x) to be quadratic, we can take g(x) = A(x + 1)(x - 4) for some constant A and \n" ); document.write( "Now, we have f(x) = A(x + 1)^2*(x - 4)^2*(x - 9) for some A. \n" ); document.write( "we use f(0) = A(1)^2*(-4)^2*(-9) = 36 \n" ); document.write( "36 = A*(1)*16*(-9) \n" ); document.write( "36 = -A*144 \n" ); document.write( "A = -1/4 \n" ); document.write( "therefore \n" ); document.write( "f(x) = (-1/4)*(x + 1)^2*(x - 4)^2*(x - 9) \n" ); document.write( "f(x) = -x^5/4+(15*x^4)/4-(55*x^3)/4-(15*x^2)/4+50*x+36\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |