document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=77118>Question 77118</A>: <I><SPAN STYLE=\"word-break: break-all;\">  (6x to the 3rd power)(-2x to the second power)(-x) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #55337 by </B><A HREF=/tutors/aboutme.mpl?userid=Ayesha><B>Ayesha(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Ayesha><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=55337\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (6x to the 3rd power)(-2x to the second power)(-x) =(216)(4)(x to the power 5)(-x) =(864)(-x to the sixth power) </SPAN>\n" );
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