document.write( "Question 911750: In Linear Equation Homework:
\n" ); document.write( "\"Matt loves biking. He bikes uphill at 4 mph, downhill at 6 mph, and manages to cover 18 miles in 4 hours. How many miles did he bike downhill?\"
\n" ); document.write( " I normally have problems with speed, distance and time. I thought maybe 18/4= something. I don't know what to do with the 4 mph and 6 mph. I know I ought to add them or something similar, but I can't decide about the mph part. Does the unit cause the question to differ? I simply can't put one end with the other.
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Algebra.Com's Answer #553362 by MathTherapy(10556)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "In Linear Equation Homework:
\n" ); document.write( "\"Matt loves biking. He bikes uphill at 4 mph, downhill at 6 mph, and manages to cover 18 miles in 4 hours. How many miles did he bike downhill?\"
\n" ); document.write( " I normally have problems with speed, distance and time. I thought maybe 18/4= something. I don't know what to do with the 4 mph and 6 mph. I know I ought to add them or something similar, but I can't decide about the mph part. Does the unit cause the question to differ? I simply can't put one end with the other.
\n" ); document.write( "Thanks.
\n" ); document.write( "

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document.write( "Let distance he biked downhill be D
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document.write( "Then distance biked uphill = 18 – D
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document.write( "We then get: D/6 + (18 - D)/4 = 4
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document.write( "2D + 3(18 – D) = 48 ------- Multiplying by LCD, 12 
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document.write( "2D + 54 – 3D = 48 
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document.write( "2D – 3D = 48 – 54 
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document.write( "- D = - 6
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document.write( "D, or distance biked, downhill = \"%28-+6%29%2F%28-+1%29\", or \"highlight_green%286%29\" miles
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document.write( "You can do the check!! 
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