document.write( "Question 911770: Five cubic dice were rolled, and the product of the numbers obtained was 432.
\n" ); document.write( "What is largest possible sum of five such numbers? \n" ); document.write( "
Algebra.Com's Answer #553360 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "We break 432 into primes:\r\n" );
document.write( "\r\n" );
document.write( "432 = 2*2*2*2*2*3*3*3\r\n" );
document.write( "\r\n" );
document.write( "To make the sum as large as possible, we have to get as many of \r\n" );
document.write( "the 5 rolls to be 6's as possible.\r\n" );
document.write( "\r\n" );
document.write( "The most number of 6's we can make by grouping the factors of 432 is 3,\r\n" );
document.write( "like this\r\n" );
document.write( "\r\n" );
document.write( "(2*3)(2*3)(2*3)*2\r\n" );
document.write( "\r\n" );
document.write( "And to make 5 factors we have to use a 1 factor:\r\n" );
document.write( "\r\n" );
document.write( "432 = 6*6*6*2*1 and 6+6+6+2+1 = 21 is the largest possible sum.\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );