document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=911751>Question 911751</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find a point M on the line y= -2x + 3 such that the slope of the line through (2,3) and M is equal to 2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #553320 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=553320\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> All points on y = -2x+3 are of the form (x,y) = (x, -2x+3)\r<BR>\n" );
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document.write( "(x1,y1) = (2,3)<BR>\n" );
document.write( "(x2,y2) = (x, -2x+3)\r<BR>\n" );
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document.write( "Slope formula\r<BR>\n" );
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document.write( "m = (y2 - y1)/(x2 - x1)\r<BR>\n" );
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document.write( "2 = (-2x+3 - 3)/(x - 2)\r<BR>\n" );
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document.write( "2 = (-2x)/(x - 2)\r<BR>\n" );
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document.write( "2(x - 2) = -2x\r<BR>\n" );
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document.write( "2x - 4 = -2x\r<BR>\n" );
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document.write( "-4 = -2x - 2x\r<BR>\n" );
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document.write( "-4 = -4x\r<BR>\n" );
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document.write( "-4x = -4\r<BR>\n" );
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document.write( "x = (-4)/(-4)\r<BR>\n" );
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document.write( "x = 1\r<BR>\n" );
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document.write( "--------------\r<BR>\n" );
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document.write( "y = -2x+3\r<BR>\n" );
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document.write( "y = -2(1)+3\r<BR>\n" );
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document.write( "y = -2+3\r<BR>\n" );
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document.write( "y = 1\r<BR>\n" );
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document.write( "So the point M is (1,1) </SPAN>\n" );
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