document.write( "Question 911743: Find the area in \"+cm%5E2+\", of a right triangle that has one acute angle to twice the other, and has a hypotenuse equal to 5 cm.
\n" ); document.write( "A) 6
\n" ); document.write( "B) \"+25sqrt%283%29%2F8+\"
\n" ); document.write( "C) \"+25sqrt%283%29%2F4+\"
\n" ); document.write( "D) 12
\n" ); document.write( "E) \"+15sqrt%283%29%2F8+\"
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Algebra.Com's Answer #553317 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let the smallest angle = \"+alpha+\"
\n" ); document.write( "The next larger angle = \"+2%2Aalpha+\"
\n" ); document.write( "It's a right triangle so the 3rd angle is \"+90+\"
\n" ); document.write( "\"+alpha+%2B+2%2Aalpha+%2B+90+=+180+\"
\n" ); document.write( "\"+3%2Aalpha+=+90+\"
\n" ); document.write( "\"+alpha+=+30+\"
\n" ); document.write( "\"+2%2Aalpha+=+60+\"
\n" ); document.write( "It is a 30-60-90 triangle
\n" ); document.write( "The sides are in the ratios:
\n" ); document.write( "\"+1+\", \"+sqrt%283%29+\", and \"+2+\"
\n" ); document.write( "------------------------------
\n" ); document.write( "The actual lengths of the sides are:
\n" ); document.write( "\"+5%2F2+\", \"+%285%2F2%29%2Asqrt%283%29+\", and \"+5+\"
\n" ); document.write( "----------------------------------
\n" ); document.write( "\"+A+=+%281%2F2%29%2A%28+5%2F2+%29%2A%28+5%2F2%29%2Asqrt%283%29+\"
\n" ); document.write( "\"+A+=+%2825%2F8%29%2Asqrt%283%29+\"
\n" ); document.write( "-----------------------
\n" ); document.write( "The answer is ( B )\r
\n" ); document.write( "\n" ); document.write( "
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