document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=911685>Question 911685</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A train leaves New York for Boston, 200 miles away, at 3:00 P.M. and averages 40 mph. Another train leaves Boston for New York on an adjacent set of tracks at 5:00 P.M. and averages 60 mph. At what time will the trains meet? (Round to the nearest minute.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #553283 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=553283\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In that 1 hour(s) from 4 to 5 the first train has gone 40 miles<BR>\n" );
document.write( "which gives it a head start of 40 miles<BR>\n" );
document.write( "new distance 160<BR>\n" );
document.write( "(40+60)*t=160<BR>\n" );
document.write( "(100)*t=160<BR>\n" );
document.write( "t=160/100<BR>\n" );
document.write( "t=1.6 hours<BR>\n" );
document.write( "1 hour<BR>\n" );
document.write( "36.0 minutes<BR>\n" );
document.write( "0 seconds<BR>\n" );
document.write( "time =1:36:0<BR>\n" );
document.write( "time =1:36 pm rounded<BR>\n" );
document.write( "The trains meet at 6:36:00<BR>\n" );
document.write( "The trains meet at 6:36 pm rounded<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );