document.write( "Question 911671: The length of a rectangle is twice the width. The area is 38 square inches.
\n" ); document.write( "a. Perimeter is = √48
\n" ); document.write( "b. You cannot calculate the perimeter with the given information.
\n" ); document.write( "c. Perimeter is ≈ 6.93 inches
\n" ); document.write( "d. Perimeter is ≈ 29.4 inches
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Algebra.Com's Answer #553270 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
The length \"L\" of a rectangle is twice the width \"W\". \r
\n" ); document.write( "\n" ); document.write( "\"L=2W\" ...eq.1\r
\n" ); document.write( "\n" ); document.write( "The area is \"A=38in%5E2\". \r
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\n" ); document.write( "\n" ); document.write( "find the perimeter \"P\":\r
\n" ); document.write( "\n" ); document.write( "\"P=2%28L%2BW%29\"\r
\n" ); document.write( "\n" ); document.write( "\"A=38in%5E2\" and \"A=L%2AW\" => \"38in%5E2=L%2AW\" \r
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\n" ); document.write( "\n" ); document.write( "\"38in%5E2=L%2AW\" ..plug in \"L=2W\"\r
\n" ); document.write( "\n" ); document.write( "\"38in%5E2=2W%2AW\" \r
\n" ); document.write( "\n" ); document.write( " \"38in%5E2=2W%5E2\" \r
\n" ); document.write( "\n" ); document.write( "\"38in%5E2%2F2=W%5E2\" \r
\n" ); document.write( "\n" ); document.write( "\"19in%5E2=W%5E2\" \r
\n" ); document.write( "\n" ); document.write( "\"sqrt%2819in%5E2%29=W\" \r
\n" ); document.write( "\n" ); document.write( "\"4.36in4W\" \r
\n" ); document.write( "\n" ); document.write( "then \"L=2W\" => \"L=2%2A4.36in\" => \"L=8.72in\"\r
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\n" ); document.write( "\n" ); document.write( "so, \"P=2%28L%2BW%29\"\r
\n" ); document.write( "\n" ); document.write( "\"P=2%288.72in%2B4.36in%29\"\r
\n" ); document.write( "\n" ); document.write( "\"P=2%2813.08in%29\"\r
\n" ); document.write( "\n" ); document.write( "\"P=26.16in%29\"\r
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\n" ); document.write( "\n" ); document.write( "so, option \"d\". Perimeter is ≈ \"29.4in\" is closest one
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