document.write( "Question 911654: maria receives 225 dollars annual interest income on two investments. if the amount she invested at 6 percent was 450 more than the amount she invested at 8 percent how much did she invest at 6 percent and at 8 percent \n" ); document.write( "
Algebra.Com's Answer #553259 by richwmiller(17219)\"\" \"About 
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We don't know the total invested.
\n" ); document.write( "We know the difference in the two accounts.
\n" ); document.write( "We know that the interest for the two accounts is $225
\n" ); document.write( "0.06*x+0.08*y=225
\n" ); document.write( "We know that the account at 6% has $450 more.
\n" ); document.write( "x=450+y
\n" ); document.write( "We substitute for x
\n" ); document.write( "0.06*(450+y)+0.08*y=225
\n" ); document.write( "We multiply out
\n" ); document.write( "27+0.06y+0.08*y=225
\n" ); document.write( "We combine like terms.
\n" ); document.write( "0.14*y=198
\n" ); document.write( "Isolate y
\n" ); document.write( "y=$1414.28571 at 8%
\n" ); document.write( "x=450+y
\n" ); document.write( "Calculate x
\n" ); document.write( "x=$1864.28571 at 6%
\n" ); document.write( "Now,we know the total invested is: 3278.57143
\n" ); document.write( "Total invested $1864.28571+$1414.28571=$3278.57143
\n" ); document.write( "We check
\n" ); document.write( "0.06*1864.28571+0.08*1414.28571=225
\n" ); document.write( "111.857143+113.142857=225
\n" ); document.write( "225.0=225
\n" ); document.write( "Since this statement is TRUE and neither x nor y is negative all is well.
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