document.write( "Question 911628: given points A(0,0), B(2,-1) and C(-2,2), find the distance from B to the midpoint of AC.\r
\n" ); document.write( "\n" ); document.write( "A)square root 13
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\n" ); document.write( "C)square root 10
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\n" ); document.write( "\n" ); document.write( "couldnt find the square root symbole so i type the squre root\r
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Algebra.Com's Answer #553219 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "given points A(0,0), B(2,-1) and C(-2,2), \r
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\n" ); document.write( "\n" ); document.write( "to find the distance from \"B+\" to the midpoint of \"AC\" we need first to find the midpoint of \"AC\"\r
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Solved by pluggable solver: Midpoint

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\n" ); document.write( " The first point is (x1,y1). The second point is (x2,y2)
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\n" ); document.write( " Since the first point is (0, 0), we can say (x1, y1) = (0, 0)
\n" ); document.write( " So \"x%5B1%5D+=+0\", \"y%5B1%5D+=+0\"
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\n" ); document.write( " Since the second point is (-2, 2), we can also say (x2, y2) = (-2, 2)
\n" ); document.write( " So \"x%5B2%5D+=+-2\", \"y%5B2%5D+=+2\"
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\n" ); document.write( " Put this all together to get: \"x%5B1%5D+=+0\", \"y%5B1%5D+=+0\", \"x%5B2%5D+=+-2\", and \"y%5B2%5D+=+2\"
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\n" ); document.write( " Finding the x coordinate of the midpoint: Add up the corresponding x coordinates x1 and x2 and divide that sum by 2
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\n" ); document.write( " X Coordinate of Midpoint = \"%28x%5B1%5D%2Bx%5B2%5D%29%2F2\"
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\n" ); document.write( " X Coordinate of Midpoint = \"%280%2B-2%29%2F2\"
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\n" ); document.write( " X Coordinate of Midpoint = \"-2%2F2\"
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\n" ); document.write( " X Coordinate of Midpoint = \"-1\"
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\n" ); document.write( " So the x coordinate of the midpoint is -1
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\n" ); document.write( " Finding the y coordinate of the midpoint: Add up the corresponding y coordinates y1 and y2 and divide that sum by 2
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\n" ); document.write( " Y Coordinate of Midpoint = \"%28y%5B1%5D%2By%5B2%5D%29%2F2\"
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\n" ); document.write( " Y Coordinate of Midpoint = \"%280%2B2%29%2F2\"
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\n" ); document.write( " Y Coordinate of Midpoint = \"2%2F2\"
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\n" ); document.write( " Y Coordinate of Midpoint = \"1\"
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\n" ); document.write( " So the y coordinate of the midpoint is 1
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\n" ); document.write( " Summary:
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\n" ); document.write( " The midpoint of the segment joining the two points (0, 0) and (-2, 2) is (-1, 1).
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\n" ); document.write( " So the answer is (-1, 1)
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\n" ); document.write( "\n" ); document.write( "now find the distance from \"B+\" to the midpoint \r
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Solved by pluggable solver: Distance Formula

\n" ); document.write( "
\n" ); document.write( " The first point is (x1,y1). The second point is (x2,y2)
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\n" ); document.write( " Since the first point is (2, -1), we can say (x1, y1) = (2, -1)
\n" ); document.write( " So \"x%5B1%5D+=+2\", \"y%5B1%5D+=+-1\"
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\n" ); document.write( " Since the second point is (-1, 1), we can also say (x2, y2) = (-1, 1)
\n" ); document.write( " So \"x%5B2%5D+=+-1\", \"y%5B2%5D+=+1\"
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\n" ); document.write( " Put this all together to get: \"x%5B1%5D+=+2\", \"y%5B1%5D+=+-1\", \"x%5B2%5D+=+-1\", and \"y%5B2%5D+=+1\"
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\n" ); document.write( " Now use the distance formula to find the distance between the two points (2, -1) and (-1, 1)
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\n" ); document.write( " \"d+=+sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2+%2B+%28y%5B1%5D+-+y%5B2%5D%29%5E2%29\"
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\n" ); document.write( " \"d+=+sqrt%28%282+-+%28-1%29%29%5E2+%2B+%28-1+-+1%29%5E2%29\" Plug in \"x%5B1%5D+=+2\", \"y%5B1%5D+=+-1\", \"x%5B2%5D+=+-1\", and \"y%5B2%5D+=+1\"
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\n" ); document.write( " \"d+=+sqrt%28%282+%2B+1%29%5E2+%2B+%28-1+-+1%29%5E2%29\"
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\n" ); document.write( " \"d+=+sqrt%28%283%29%5E2+%2B+%28-2%29%5E2%29\"
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\n" ); document.write( " \"d+=+sqrt%289+%2B+4%29\"
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\n" ); document.write( " \"d+=+sqrt%2813%29\"
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\n" ); document.write( " \"d+=+3.60555127546399\"
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\n" ); document.write( " Answer:
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\n" ); document.write( " The distance between the two points (2, -1) and (-1, 1) is exactly \"sqrt%2813%29\" units
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\n" ); document.write( " The approximate distance between the two points is about 3.60555127546399 units
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\n" ); document.write( " So again,
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\n" ); document.write( " Exact Distance: \"sqrt%2813%29\" units
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\n" ); document.write( " Approximate Distance: \"3.60555127546399\" units
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