document.write( "Question 911586: The income from an 8% investment is $300 more than the income from a 6% investment. How much invested at each rate? If a total of $30000 invested? \n" ); document.write( "
Algebra.Com's Answer #553191 by dkppathak(439)\"\" \"About 
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The income from an 8% investment is $300 more than the income from a 6% investment. How much invested at each rate? If a total of $30000 invested?
\n" ); document.write( "let $ X invested at 8%
\n" ); document.write( "and $ 30000-X at 6%
\n" ); document.write( "0.08X-.06(30000-X)=300
\n" ); document.write( ".08x+0.06x-1800=300
\n" ); document.write( ".14x=300+1800
\n" ); document.write( ".14x=2100
\n" ); document.write( "x=2100/.14=15000
\n" ); document.write( "other amount will be 30000-15000=15000
\n" ); document.write( "both investment are $15000 at 8%
\n" ); document.write( "and investment at 6% also $15000
\n" ); document.write( "Answer $15000 at 8%
\n" ); document.write( " $15000 at 6%
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