document.write( "Question 911584: Consider selecting one card at a time without replacement from a 52-card deck. Let event A be the first card is a heart, and event B be the second card is a heart
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document.write( "1. What is the probability that the first card is a heart and the second card is also a heart(express in the simplest fraction form)\r
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document.write( "2. What is the probability that the second card is a heart, given that the first card is a heart (express the answer in simplest fraction form)\r
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document.write( "3. Are A and B independent? Why or Why not? \n" );
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Algebra.Com's Answer #553187 by stanbon(75887) ![]() You can put this solution on YOUR website! Consider selecting one card at a time without replacement from a 52-card deck. Let event A be the first card is a heart, and event B be the second card is a heart \n" ); document.write( " 1. What is the probability that the first card is a heart and the second card is also a heart(express in the simplest fraction form) \n" ); document.write( "Ans:: (4/52)(3/51) or 4C2/52C2 = 0.0045 \n" ); document.write( "------------------------------------------------------------- \n" ); document.write( " 2. What is the probability that the second card is a heart, given that the first card is a heart (express the answer in simplest fraction form) \n" ); document.write( "P(heart | heart) = P(heart and heart)/P(heart) = 52C2/52C4 = 0.0049 \n" ); document.write( "--------------- \n" ); document.write( " 3. Are A and B independent? Why or Why not? \n" ); document.write( "Ans: no, because P(heart and heart) is not equal to P(heart | heart) \n" ); document.write( "============= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |