document.write( "Question 911573: Sketch the graph of: 𝑥 = (1/4)𝑦^2 − 2𝑦 − 1 \n" ); document.write( "
Algebra.Com's Answer #553184 by stanbon(75887)\"\" \"About 
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\n" ); document.write( "y = (1/4)x^2 - 2x -1
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\n" ); document.write( "Find the vertex at x = -b/(2a) = 2/(2(1/4)) = 4
\n" ); document.write( "Then f(4) = (1/4)(4^2) - 2*4 -1 = 4-8-1 = -5----
\n" ); document.write( "Plot the point (4,-5)
\n" ); document.write( "That is the minimum point of the graph since (1/4) is positive.
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\n" ); document.write( "Find the y-intercept::
\n" ); document.write( "f(0) = -1
\n" ); document.write( "Plot the point (0,-1)
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\n" ); document.write( "Sketch a parabola with that vertex that opens up to intersect (0,-1)
\n" ); document.write( "----
\n" ); document.write( "\"graph%28400%2C400%2C-10%2C10%2C-10%2C10%2C%281%2F4%29x%5E2-2x-1%29\"
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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