document.write( "Question 911506: Jessica has half of her investments in stock paying a
\n" ); document.write( "7%
\n" ); document.write( "dividend and the other half in a stock paying
\n" ); document.write( "13%
\n" ); document.write( "interest. If her total annual interest is
\n" ); document.write( "$780
\n" ); document.write( ", how much does she have invested?
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Algebra.Com's Answer #553131 by richwmiller(17219)\"\" \"About 
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Stop spreading the problem out to make it look bigger.\r
\n" ); document.write( "\n" ); document.write( "We know that the interest for the two accounts is $780
\n" ); document.write( "0.07*x+0.13*y=780
\n" ); document.write( "We know that the account at 7% has 1 times the amount at 13%
\n" ); document.write( "We substitute for x
\n" ); document.write( "0.07*(1*y)+0.13*y=780
\n" ); document.write( "We multiply out
\n" ); document.write( "(0.07+0.13)*y=780
\n" ); document.write( "We combine like terms.
\n" ); document.write( "0.2*y=780
\n" ); document.write( "Isolate y
\n" ); document.write( "y= 3900.00
\n" ); document.write( "y=$ 3900.00 at 13%
\n" ); document.write( "Calculate x
\n" ); document.write( "x=1*y
\n" ); document.write( "x=$ 3900.00 at 7%
\n" ); document.write( "Your total for x is $ 3900.00
\n" ); document.write( "Your total for y is $ 3900.00
\n" ); document.write( "Your total for x and y is $ 7800.00
\n" ); document.write( "Total invested $ 3900.00 + $ 3900.00=$ 7800.00
\n" ); document.write( "We check
\n" ); document.write( "0.07* 3900.00+0.13* 3900.00=780
\n" ); document.write( " 273.00+ 507.00=780
\n" ); document.write( "780=780
\n" ); document.write( "Since this statement is TRUE and neither x nor y is negative then all is well.
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