document.write( "Question 911502: If one solution is 20% acid and another 50% acid, then how many liters of each must be mixed to get 20 liters of solution that is 40% acid? \n" ); document.write( "
Algebra.Com's Answer #553121 by richwmiller(17219)\"\" \"About 
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We need a total of 20 liter at 40%
\n" ); document.write( "We want to know how many liter at 20% to mix with 50%
\n" ); document.write( "a+b=20,
\n" ); document.write( "0.2*a+0.5*b=0.4*20
\n" ); document.write( "a=20-b
\n" ); document.write( "0.2*(20-b)+0.5*b=8
\n" ); document.write( "4-0.2b+0.5*b=8
\n" ); document.write( "0.3*b=4
\n" ); document.write( "b=13.3333333
\n" ); document.write( "a=20-b
\n" ); document.write( "a=6.66666667 liter at 20%
\n" ); document.write( "b=13.3333333 liter at 50%
\n" ); document.write( "check
\n" ); document.write( "0.2*6.66666667+0.5*13.3333333=0.4*20
\n" ); document.write( "1.33333333+6.66666667=8
\n" ); document.write( "8.0=8
\n" ); document.write( "ok
\n" ); document.write( "codemx1
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