document.write( "Question 911502: If one solution is 20% acid and another 50% acid, then how many liters of each must be mixed to get 20 liters of solution that is 40% acid? \n" ); document.write( "
Algebra.Com's Answer #553121 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! We need a total of 20 liter at 40% \n" ); document.write( "We want to know how many liter at 20% to mix with 50% \n" ); document.write( "a+b=20, \n" ); document.write( "0.2*a+0.5*b=0.4*20 \n" ); document.write( "a=20-b \n" ); document.write( "0.2*(20-b)+0.5*b=8 \n" ); document.write( "4-0.2b+0.5*b=8 \n" ); document.write( "0.3*b=4 \n" ); document.write( "b=13.3333333 \n" ); document.write( "a=20-b \n" ); document.write( "a=6.66666667 liter at 20% \n" ); document.write( "b=13.3333333 liter at 50% \n" ); document.write( "check \n" ); document.write( "0.2*6.66666667+0.5*13.3333333=0.4*20 \n" ); document.write( "1.33333333+6.66666667=8 \n" ); document.write( "8.0=8 \n" ); document.write( "ok \n" ); document.write( "codemx1 \n" ); document.write( " \n" ); document.write( " |