document.write( "Question 911466: Please help me solve this question tried my best but couldn't answer it!
\n" ); document.write( " Question: In quadrilateral ABCD, m/A=(x-10), m/B=(2x+10), m/C=(2x-70) m/D(3x-50).What kind of quadrilateral ia ABCD? Why? \n" ); document.write( "
Algebra.Com's Answer #553102 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
In quadrilateral ABCD, m/A=(x-10), m/B=(2x+10), m/C=(2x-70) m/D(3x-50)\r
\n" ); document.write( "\n" ); document.write( "Sum of angles of quadrilateral = 360 deg\r
\n" ); document.write( "\n" ); document.write( "(x-10)+(2x+10)+(2x-70)+(3x-50)=360\r
\n" ); document.write( "\n" ); document.write( "8x-120=360
\n" ); document.write( "6x=360+120
\n" ); document.write( "8x=480\r
\n" ); document.write( "\n" ); document.write( "x=60\r
\n" ); document.write( "\n" ); document.write( " m/A=(x-10),=50
\n" ); document.write( " m/B=(2x+10),130
\n" ); document.write( " m/C=(2x-70) 50
\n" ); document.write( "m/D(3x-50)130\r
\n" ); document.write( "\n" ); document.write( "The opposite angles are equal
\n" ); document.write( "Hence its a parallelogram\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );