document.write( "Question 77196This question is from textbook
\n" ); document.write( ": \"+sqrt+%2850+%2B+7k%29+\" = (k + 8)\r
\n" ); document.write( "\n" ); document.write( "I am supposed to figure out what the variable is. So far, I have squared both sides so the \"50 + 7k\" is no longer a square root. and the k is squared and 8 is now 64. From there, I subtracted 50 from both sides, but then I got to a place where I had to find the square root of \"7k\" and then i got totally lost. Would you be able to help me? Thank you.
\n" ); document.write( "

Algebra.Com's Answer #55310 by avidreader27(9)\"\" \"About 
You can put this solution on YOUR website!
The first problem occured when you tried to square (k+8). The answer would not be K^2 and 64. The square that, you need to multiply like this:\r
\n" ); document.write( "\n" ); document.write( "(k+8)(k+8) which gives: k^2+16k+64.\r
\n" ); document.write( "\n" ); document.write( "You then have:\r
\n" ); document.write( "\n" ); document.write( "50+7k = k^2+16k=64\r
\n" ); document.write( "\n" ); document.write( "move the 50 and 7k to the other side:\r
\n" ); document.write( "\n" ); document.write( "k^2+9k+14=0\r
\n" ); document.write( "\n" ); document.write( "then you factor this equation:\r
\n" ); document.write( "\n" ); document.write( "(k+7)(k+2)\r
\n" ); document.write( "\n" ); document.write( "setting each of these = to 0 to solve for k you get:\r
\n" ); document.write( "\n" ); document.write( "k+7=0 and k+2=0\r
\n" ); document.write( "\n" ); document.write( "k= -7 or -2 <---- answer\r
\n" ); document.write( "\n" ); document.write( "Hope this helps!!!
\n" ); document.write( "
\n" );