document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=77195>Question 77195</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0201719665/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+sqrt+%286x%2B7%29+ ALIGN=MIDDLE  ALT=\"+sqrt+%286x%2B7%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > - <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+sqrt+%283x%2B3%29+ ALIGN=MIDDLE  ALT=\"+sqrt+%283x%2B3%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 1\r<BR>\n" );
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document.write( "I am supposed to solve the radical equations for the variable. I started out by thinking I should separate each of the numbers and factor as best I could. So then I had:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+sqrt+%283x%29+ ALIGN=MIDDLE  ALT=\"+sqrt+%283x%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > * <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+sqrt+%282%29+ ALIGN=MIDDLE  ALT=\"+sqrt+%282%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > + 7 - <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+sqrt+%283x%29+ ALIGN=MIDDLE  ALT=\"+sqrt+%283x%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+sqrt+%283%29+ ALIGN=MIDDLE  ALT=\"+sqrt+%283%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 1\r<BR>\n" );
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document.write( "After that, I didn't think that the <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+sqrt+%283x%29+ ALIGN=MIDDLE  ALT=\"+sqrt+%283x%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > could cancel each other out because then there would be no variable, so I am currently stuck right there. I would be really grateful if you let me know if I am on the right track, or if I am really off, help me get on track. Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #55309 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=55309\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sqrt (6x+7)  -  sqrt (3x+3)  = 1\r<BR>\n" );
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document.write( "Square it the way it is so you end up with just one new radical:\r<BR>\n" );
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document.write( "Result of square both sides is:<BR>\n" );
document.write( "6x+7 -2sqrt[(6x+7)(3x+3)] + 3x+3 = 1\r<BR>\n" );
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document.write( "Isolate the remaining radical:\r<BR>\n" );
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document.write( "9x+10 - 2[....] = 1<BR>\n" );
document.write( "2[....]= 9x+9<BR>\n" );
document.write( "Square to get rid of the radical:<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "4[(6x+7)(3x+3) = [9(x+1)]^2<BR>\n" );
document.write( "Now, solve for x.<BR>\n" );
document.write( "I'll leave that to you.<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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