document.write( "Question 911400: In investing $6,600 of a couple's money, a financial planner put some of it into a savings account paying 3% annual interest. The rest was invested in a riskier mini-mall development plan paying 9% annually. The combined interest earned for the first year was $426. How much money was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #553067 by richwmiller(17219)\"\" \"About 
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Total amount of money invested: $6600
\n" ); document.write( "x+y=6600,
\n" ); document.write( "Total yearly interest for the two accounts is: $426
\n" ); document.write( "0.03*x+0.09*y=426
\n" ); document.write( "x=6600-y
\n" ); document.write( "Substitute for x
\n" ); document.write( "0.03*(6600-y)+0.09*y=426
\n" ); document.write( "Multiply out
\n" ); document.write( "198-0.03*y+0.09*y=426
\n" ); document.write( "Combine like terms.
\n" ); document.write( "0.06*y=228
\n" ); document.write( "Isolate y
\n" ); document.write( "y=$ 3800.00 at 9% earns $342 interest
\n" ); document.write( "x=6600-y
\n" ); document.write( "Calculate x
\n" ); document.write( "x=$ 2800.00 at 3% earns $84 interest
\n" ); document.write( "Check
\n" ); document.write( "0.03*2800+0.09*3800=426
\n" ); document.write( "84+342=426
\n" ); document.write( "426=426
\n" ); document.write( "If this statement is TRUE and neither x nor y is negative then all is well
\n" ); document.write( "code int1\r
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