document.write( "Question 911363: Bay city and Vernonville are 330 miles apart. A car leaves Bay City traveling towards Vernonville, and another car leaves Vernonville at the same time, traveling towards Bay City. They meet after 3 hours. Find the rate of each car if the car leaving Bay City travels 40 miles per hour faster than the other car.
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Algebra.Com's Answer #553065 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! 3*x+3*(x+40)=330 \n" ); document.write( "3*(2x+40)=330 \n" ); document.write( "6x+120=330 \n" ); document.write( "6x=210 \n" ); document.write( "x=35 mph for the slower car \n" ); document.write( "x+40=75 mph for the faster car \n" ); document.write( "check \n" ); document.write( "3*35+3*75=330 \n" ); document.write( "105+225=330 \n" ); document.write( "ok \n" ); document.write( " |