document.write( "Question 911346: You have already invested $450 in a stock with an annual return of 11%. How much of an additional $1,200 should be invested at 12% and how much at 6% so that the total return on the entire $1,650 is 9%? \n" ); document.write( "

Algebra.Com's Answer #553043 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+x+\"$ = amount to be invested @ 12%
\n" ); document.write( "Let $\"+1200+-+x+\"$ = amount to be invested @ 6%
\n" ); document.write( "-------------------
\n" ); document.write( " $\"+.11%2A450+%2B+.12x+%2B+.06%2A%28+1200+-+x+%29+=+.09%2A1650+\"$
\n" ); document.write( " $\"+49.5+%2B+.12x+%2B+72+-+.06x+=+148.5\"$
\n" ); document.write( " $\"+.06x+%2B+121.5+=+148.5+\"$
\n" ); document.write( " $\"+.06x+=+27+\"$
\n" ); document.write( " $\"+x+=+450+\"$
\n" ); document.write( " $\"+1200+-+x+=+750+\"$
\n" ); document.write( "-------------------
\n" ); document.write( "$450 should be invested @12%
\n" ); document.write( "$750 should be invested @ 6%
\n" ); document.write( "------------
\n" ); document.write( "check:
\n" ); document.write( " $\"+.11%2A450+%2B+.12x+%2B+.06%2A%28+1200+-+x+%29+=+.09%2A1650+\"$
\n" ); document.write( " $\"+.11%2A450+%2B+.12%2A450+%2B+.06%2A%28+1200+-+450+%29+=+.09%2A1650+\"$
\n" ); document.write( " $\"+49.5+%2B+54+%2B+.06%2A750+=+148.5+\"$
\n" ); document.write( " $\"+103.5+%2B+45+=+148.5+\"$
\n" ); document.write( " $\"+148.5+=+148.5+\"$
\n" ); document.write( "OK
\n" ); document.write( " \n" ); document.write( "

\n" );