document.write( "Question 77180This question is from textbook
\n" ); document.write( ": If 800ml of a juice drink is 15% grape juice, how much grape juice should be added to make a drink that is 20% grape juice? \n" ); document.write( "
Algebra.Com's Answer #55299 by rajagopalan(174)\"\" \"About 
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Dear Student,\r
\n" ); document.write( "\n" ); document.write( "You have to work cool to arrive at the answer:
\n" ); document.write( "Let us add x ml of grape juice to the old juice
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\n" ); document.write( "Old Juice...800 ml....15%grape=120....ml grape juice
\n" ); document.write( "new Juice...800+x ml....20%grape=120+x..ml grape juice\r
\n" ); document.write( "\n" ); document.write( "now we get (120+x)/(800+x)=20/100 (ie 20%=20/100)
\n" ); document.write( "solving the first degree eqn\r
\n" ); document.write( "\n" ); document.write( "(120+x)/(800+x)=20/100
\n" ); document.write( "100(120+x)=20(800+x)
\n" ); document.write( "expanding 12000+100x=16000+20x
\n" ); document.write( "100x-20x=16000-12000
\n" ); document.write( "80x=4000
\n" ); document.write( "x=4000/80=50 ml
\n" ); document.write( "so you add 50 ml of fresh grape juice to make it 20% conventrate.\r
\n" ); document.write( "\n" ); document.write( "Cross verification:\r
\n" ); document.write( "\n" ); document.write( "new juice...grape=120+50=170 ml
\n" ); document.write( "nrw juice total =800+50 =850 ml
\n" ); document.write( "so % grape =170/850=20%
\n" ); document.write( "okay
\n" ); document.write( "good day !!
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