document.write( "Question 77182: I can't seem to get this one started. Please help.\r
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document.write( "Kathy can paint a house in 15 hours. With Jane's help it takes only 6 hours. How long would it take Jane by herself? \n" );
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Algebra.Com's Answer #55298 by rajagopalan(174)![]() ![]() You can put this solution on YOUR website! kathy....takes...15..hours ..means she paints 1/15 per hour...(A) \n" ); document.write( "kathy+Jane..take..6.. hours ..means they paint 1/6 per hour(..B) \n" ); document.write( "So Jane alone paints (1/6)-(1/15) per hour ..(B-A)= \n" ); document.write( "simplifying, 1/6 minus 1/15=5/30 minus 2/30 = 3/30=1/10\r \n" ); document.write( "\n" ); document.write( "1/10th of the house is painted in one hour by Jane \n" ); document.write( "For full house she will consume 10 hours (invert 1/10)\r \n" ); document.write( "\n" ); document.write( "Cross check \n" ); document.write( "Kathy in one hour 1/15 \n" ); document.write( "Jane in one hour 1/10 \n" ); document.write( "Both in one hour 1/15..+1/10 = 2/30..+3/30=5/30=1/6 \n" ); document.write( "So they will take 6 hours to finish the hoe painting..OK \n" ); document.write( "Good day.. \r \n" ); document.write( "\n" ); document.write( "Answer: It takes Jane 10 hours to finish it herself.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |