document.write( "Question 911252: A truck can travel 315 miles in the same time that it takes a car to travel 360 miles. if the trucks rate is 5 mph slower than the car's,find the average rate for each \n" ); document.write( "
Algebra.Com's Answer #552968 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! r*t=d \n" ); document.write( "t=d/r \n" ); document.write( "t=315/r \n" ); document.write( "(r+5)*t=360 \n" ); document.write( "t=360/(r+5) \n" ); document.write( "t=315/r \n" ); document.write( "315/r=360/(r+5) \n" ); document.write( "360*r=315*(r+5) \n" ); document.write( "360*r=315*r+315*5 \n" ); document.write( "45*r=315*5 \n" ); document.write( "r=1575/(45) \n" ); document.write( "r=35 mph truck \n" ); document.write( "r+5=40 mph car \n" ); document.write( "codeddfst \n" ); document.write( " |