document.write( "Question 911252: A truck can travel 315 miles in the same time that it takes a car to travel 360 miles. if the trucks rate is 5 mph slower than the car's,find the average rate for each \n" ); document.write( "
Algebra.Com's Answer #552968 by richwmiller(17219)\"\" \"About 
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r*t=d
\n" ); document.write( "t=d/r
\n" ); document.write( "t=315/r
\n" ); document.write( "(r+5)*t=360
\n" ); document.write( "t=360/(r+5)
\n" ); document.write( "t=315/r
\n" ); document.write( "315/r=360/(r+5)
\n" ); document.write( "360*r=315*(r+5)
\n" ); document.write( "360*r=315*r+315*5
\n" ); document.write( "45*r=315*5
\n" ); document.write( "r=1575/(45)
\n" ); document.write( "r=35 mph truck
\n" ); document.write( "r+5=40 mph car
\n" ); document.write( "codeddfst
\n" ); document.write( "
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