document.write( "Question 911252: A truck can travel 315 miles in the same time that it takes a car to travel 360 miles. if the trucks rate is 5 mph slower than the car's,find the average rate for each \n" ); document.write( "
Algebra.Com's Answer #552947 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "r the car's speed
\n" ); document.write( "t = D/r, times equal the question states
\n" ); document.write( "\"315%2F%28r-5%29+=+360%2Fr\"
\n" ); document.write( "315r = 360r - 1800
\n" ); document.write( "1800 = 45r
\n" ); document.write( "40mph = r, the car's speed. the truck 35mph\"40-5\"
\n" ); document.write( "and checking...
\n" ); document.write( "\"315%2F35+=+360%2F40\"
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