document.write( "Question 911241: How many gallons of a 50% alcohol solution must be mixed with 30 gallons of an 18% solution to obtain a solution that is 40% alcohol?
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Algebra.Com's Answer #552935 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! .50x + .18(30G) = .40(30G + x) \n" ); document.write( "x = .22(30G)/.10, gallons of a 50% alcohol solution that must be used \n" ); document.write( " |