document.write( "Question 911148: The sum of three consecutive integers is 15 more than twice the smallest integer. Find the integers. \n" ); document.write( "
Algebra.Com's Answer #552878 by DN(2)![]() ![]() You can put this solution on YOUR website! Let x be any integer.Then x, x+1, x+2 are three consecutive integers and x is the smallest of the three. \r \n" ); document.write( "\n" ); document.write( "then x+(x+1)+(x+2)=2x+15 \n" ); document.write( "=> x+x+1+x+2 =2x+15 \n" ); document.write( "=> x+x+x+1+2 =2x+15 \n" ); document.write( "=> 3x+3 =2x+15 \n" ); document.write( "=> 3x-2x =15-3 \n" ); document.write( "=> x =12 \n" ); document.write( "Therefore, 12, 13, 14 are the integers\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |