document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=911107>Question 911107</A>: <I><SPAN STYLE=\"word-break: break-all;\"> XY=14 and x+y=9 then x-y=<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #552847 by </B><A HREF=/tutors/aboutme.mpl?userid=anirudhreddy><B>anirudhreddy(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=anirudhreddy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=552847\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> XY=14 and x+y=9 then x-y=\r<BR>\n" );
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document.write( "to solve the above problem we need to learn basic formulas like 1)(a+b)^2= a^2+b^2+2ab. and 2)(a-b)^2=a^2+b^2-2ab.<BR>\n" );
document.write( "now apply the above formulas to given data by squaring both sides for x+y=9<BR>\n" );
document.write( "==> (x+y)^2=9^2 ==> x^2+y^2+2xy=81, now assign given assign values to xy <BR>\n" );
document.write( "==> x^2+y^2+2(14)=81 ==> x^2+y^2= 81-28. ==> x^2+y^2= 53. <BR>\n" );
document.write( "now apply this x^2+y^2 values to formula 2. (x-y)^2=x^2+y^2-2xy. <BR>\n" );
document.write( "==> (x-y)^2= 53-28 ==> (x-y)^2= 25. ==> now taking sq.root on both sides and we get the x-y values as x-y=5. </SPAN>\n" );
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