document.write( "Question 911088: The perimeter of a rectangle is 64 meters and its area is 253m^2. Find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #552843 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Unknown dimensions, x and y;
\n" ); document.write( "Given p perimeter and A area.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"system%28A=xy%2Cp=2x%2B2y%29\"\r
\n" ); document.write( "\n" ); document.write( "\"2y=p-2x\"
\n" ); document.write( "\"y=%28p-2x%29%2F2\"
\n" ); document.write( "Substitute this into A equation.
\n" ); document.write( "\"xy=A\"
\n" ); document.write( "\"x%28p-2x%29%2F2=A\"
\n" ); document.write( "\"px-2x%5E2=2A\"
\n" ); document.write( "\"px-2x%5E2-2A=0\"
\n" ); document.write( "\"-2x%5E2%2Bpx-2A=0\"
\n" ); document.write( "\"2x%5E2-px%2B2A=0\"
\n" ); document.write( "\"x=%28p%2B-sqrt%28p%5E2-4%2A2%2A2A%29%29%2F%282%2A2%29\"
\n" ); document.write( "guessing that the PLUS square root form will be wanted,
\n" ); document.write( "\"highlight%28x=%28p%2Bsqrt%28p%5E2-16A%29%29%2F4%29\"\r
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\n" ); document.write( "\n" ); document.write( "The easiest way to continue is to substitute for the given values for p and A and evaluate x.
\n" ); document.write( "Find y using what you found for the value of x, any equation found to be convenient;
\n" ); document.write( "maybe directly in \"y=A%2Fx\".\r
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\n" ); document.write( "\n" ); document.write( "p=64, and A=253.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x=%2864%2Bsqrt%2864%5E2-16%2A253%29%29%2F4\"
\n" ); document.write( "\"x=%2864%2Bsqrt%2848%29%29%2F4\"
\n" ); document.write( "\"x=%2864%2B4%2Asqrt%283%29%29%2F4\"
\n" ); document.write( "\"highlight%28x=16%2Bsqrt%283%29%29\"---one of the dimensions\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y=253%2Fx\"
\n" ); document.write( "\"y=253%2F%2816%2Bsqrt%283%29%29\"
\n" ); document.write( "\"y=%28253%2F%2816%2Bsqrt%283%29%29%29%2816-sqrt%283%29%29%2F%2816-sqrt%283%29%29\"
\n" ); document.write( "\"y=%28253%2816-sqrt%283%29%29%29%2F%2816%5E2-3%29\"
\n" ); document.write( "\"y=%28253%2816-sqrt%283%29%29%29%2F253\"
\n" ); document.write( "\"highlight%28y=16-sqrt%283%29%29\"----other dimension
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